121x^2+44x+2=0

Solution for 121x^2+44x+2=0 equation:

121x^2+44x+2=0

a = 121; b = 44; c = +2;
Δ = b2-4ac
Δ = 442-4·121·2
Δ = 968
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{968}=\sqrt{484*2}=\sqrt{484}*\sqrt{2}=22\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-22\sqrt{2}}{2*121}=\frac{-44-22\sqrt{2}}{242}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+22\sqrt{2}}{2*121}=\frac{-44+22\sqrt{2}}{242}
$